Classifying Quadrics using Exact Arithmetic
نویسنده
چکیده
2.1 The Case All di 6= 0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 2.2 The Case d0 = 0 < d1 ≤ d2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4 2.3 The Case d0 < 0 = d1 < d2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4 2.4 The Case d0 ≤ d1 < d2 = 0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4 2.5 The Case d0 = d1 = 0 < d2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5 2.6 The Case d0 < 0 = d1 = d2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5 2.7 The Case d0 = d1 = d2 = 0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5
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